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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    In a parallel plate condenser, the radius of each circular plate is \[12cm\] and the distance between the plates is\[5mm\]. There is a glass slab of \[3mm\] thick and of radius \[12cm\] with dielectric constant 6 between its plates. The capacity of the condenser will be

    A)                    \[144\times {{10}^{-9}}F\]

    B)                                      \[40pF\]

    C)                    \[160pF\]                       

    D)            \[1.44\mu F\]

    Correct Answer: C

    Solution :

               \[C=\frac{{{\varepsilon }_{0}}A}{d-t+\frac{t}{K}}=\frac{1}{4\pi \times 9\times {{10}^{9}}}.\frac{\pi \,{{(0.12)}^{2}}}{\left( 2+\frac{1}{2} \right)\,{{10}^{-3}}}\] \[=\frac{2\times 144\times {{10}^{-10}}}{36\times 5}=160pF\]


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