JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    A 4 mF condenser is charged to 400 V and then its plates are joined through a resistance. The heat produced in the resistance is                                                                  [UPSEAT 2004]

    A)                    0.16 J

    B)                                      0.32 J

    C)                    0.64 J

    D)                                      1.28 J

    Correct Answer: B

    Solution :

               \[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(400)}^{2}}=0.32J\]


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