A) Increases
B) Decreases
C) Remains unchanged
D) Becomes zero
Correct Answer: A
Solution :
Energy \[U=\frac{1}{2}\frac{{{Q}^{2}}}{C}\] for a charged capacitor charge Q is constant and with the increase in separation C will decrease \[\left( C\propto \frac{1}{d} \right)\], So overall U will increase.You need to login to perform this action.
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