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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    The work done in placing a charge of \[8\times {{10}^{-18}}\] coulomb on a condenser of capacity 100 micro-farad is                    [AIEEE 2003]

    A)            \[32\times {{10}^{-32}}\,Joule\]                                      

    B)            \[16\times {{10}^{-32}}\,Joule\]

    C)            \[3.1\times {{10}^{-26}}\,Joule\]                                    

    D)            \[4\times {{10}^{-10}}\,Joule\]

    Correct Answer: A

    Solution :

               \[W=\frac{{{Q}^{2}}}{2C}=\frac{{{(8\times {{10}^{-18}})}^{2}}}{2\times 100\times {{10}^{-6}}}=32\times {{10}^{-32}}J\]


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