A) \[Volt/{{m}^{2}}\]
B) Joule/coulomb
C) Farad/m
D) Henry/m
Correct Answer: C
Solution :
\[C=\frac{{{\varepsilon }_{0}}A}{d}\] Þ \[{{\varepsilon }_{0}}=\frac{Cd}{A}\] Þ \[{{\varepsilon }_{0}}\]® \[\frac{Farad\times m}{{{m}^{2}}}\to \frac{F}{m}\]
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