A) \[\text{25}\times \text{1}{{0}^{\text{5}}}Joule\]
B) 25 Joule
C) 25 ´ 10 erg
D) \[\text{25}\times \text{1}{{0}^{\text{3}}}erg\]
Correct Answer: D
Solution :
\[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times 2\times {{10}^{-6}}\times {{(50)}^{2}}=25\times {{10}^{-4}}J\] \[=25\times {{10}^{3}}erg\]
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