A) \[120\,m\,F\]
B) \[120\,\mu \,F\]
C) \[24\,\mu \,F\]
D) \[24\,m\,F\]
Correct Answer: A
Solution :
\[U=\frac{1}{2}C{{V}^{2}}\]so\[24\times 60\times 60=\frac{1}{2}C{{(1200)}^{2}}\]Þ C=120 mF
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