A) 8 times
B) 4 times
C) 2 times
D) 32 times
Correct Answer: C
Solution :
Volume of 8 small drops = Volume of big drop \[8\times \frac{4}{3}\pi {{r}^{3}}=\frac{4}{3}\pi {{R}^{3}}\] Þ R = 2r As capacity is r, hence capacity becomes 2 times.
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