2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electrostatics & Capacitance

JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    The capacity of a parallel plate condenser is \[5\mu F\]. When a glass plate is placed between the plates of the conductor, its potential becomes \[1/8th\]of the original value. The value of dielectric constant will be                                      [MP PMT 1985]

    A)                    1.6                                    

    B)            5

    C)                    8

    D)                                      40

    Correct Answer: C

    Solution :

               \[V'=\frac{V}{8}\] Þ \[\frac{V}{K}=\frac{V}{8}\] Þ K = 8


You need to login to perform this action.
You will be redirected in 3 sec spinner