A) \[\frac{1}{\sqrt{2}}\]
B) \[\sqrt{2}\]
C) \[\frac{1}{2\sqrt{2}}\]
D) \[2\sqrt{2}\]
Correct Answer: D
Solution :
\[\frac{{{B}_{c}}}{{{B}_{a}}}={{\left( 1+\frac{{{x}^{2}}}{{{a}^{2}}} \right)}^{3/2}}={{\left( 1+\frac{{{a}^{2}}}{{{a}^{2}}} \right)}^{3/2}}={{\left( 1+1 \right)}^{3/2}}=2\sqrt{2}\]
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