A) \[\frac{{{\mu }_{0}}ne}{2r}\]
B) \[\frac{{{\mu }_{0}}{{n}^{2}}e}{2r}\]
C) \[\frac{{{\mu }_{0}}ne}{2\pi r}\]
D) Zero
Correct Answer: A
Solution :
Corresponding current i = en So \[B=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi \left( en \right)}{r}=\frac{{{\mu }_{0}}ne}{2r}\]
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