A) \[3.14\times {{10}^{-2}}weber/{{m}^{2}}\]
B) \[6.28\times {{10}^{-2}}weber/{{m}^{2}}\]
C) \[9.42\times {{10}^{-2}}weber/{{m}^{2}}\]
D) \[12.56\times {{10}^{-2}}weber/\,{{m}^{2}}\]
Correct Answer: B
Solution :
\[B={{\mu }_{0}}ni=4\pi \times {{10}^{-7}}\times \frac{200}{{{10}^{-2}}}\times 2.5\]\[=6.28\times {{10}^{-2}}Wb/{{m}^{2}}\]
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