A) \[\frac{2\pi q}{nr}\times {{10}^{-7}}\] N/amp/metre
B) \[\frac{2\pi q}{r}\times {{10}^{-7}}\] N/amp/metre
C) \[\frac{2\pi nq}{r}\times {{10}^{-7}}\]N/amp/metre
D) \[\frac{2\pi q}{r}\] N/amp/metre
Correct Answer: C
Solution :
The magnetic field at the centre of the circle \[=\frac{{{\mu }_{o}}}{4\pi }\times \frac{2\pi i}{r}={{10}^{-7}}\times \frac{2\pi (nq)}{r}=\frac{2\pi nq}{r}\times {{10}^{-7}}N/A\text{-}m\]
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