JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Biot-savart's Law and Amperes Law

  • question_answer
    An arc of a circle of radius R subtends an angle \[\frac{\pi }{2}\] at the centre. It carries a current i. The magnetic field at the centre will be                                                  [MP PET 2003]

    A)            \[\frac{{{\mu }_{0}}i}{2R}\]   

    B)            \[\frac{{{\mu }_{0}}i}{8R}\]

    C)            \[\frac{{{\mu }_{0}}i}{4R}\]   

    D)            \[\frac{2{{\mu }_{0}}i}{5R}\]

    Correct Answer: B

    Solution :

               \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{\theta i}{r}=\frac{{{\mu }_{0}}}{4\pi }\times \frac{\pi }{2}\times \frac{i}{R}=\frac{{{\mu }_{0}}i}{8R}\]


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