A) \[5.4\times {{10}^{-2}}\,weber/{{m}^{2}}\]
B) \[2.7\times {{10}^{-2}}\,weber/{{m}^{2}}\]
C) \[1.35\times {{10}^{-2}}\,weber/{{m}^{2}}\]
D) \[0.675\times {{10}^{-2}}\,weber/{{m}^{2}}\]
Correct Answer: B
Solution :
Magnetic field at the centre of solenoid \[(B)={{\mu }_{0}}ni\] Where n = Number of turns /meter \[\therefore \,B=4\pi \times {{10}^{-7}}\times 4250\times 5=2.7\times {{10}^{-2}}Wb/{{m}^{2}}\]
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