JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Biot-savart's Law and Amperes Law

  • question_answer
    A long solenoid is formed by winding 20 turns/cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately \[(\frac{{{\mu }_{0}}}{4\pi }={{10}^{-7}}\,tesla-metre/ampere)\]              [MP PMT 1994]

    A)            8.0 A                                        

    B)            4.0 A

    C)            2.0 A                                        

    D)            1.0 A

    Correct Answer: A

    Solution :

                       \[B={{\mu }_{0}}ni\Rightarrow i=\frac{B}{{{\mu }_{0}}n}\]\[=\frac{20\times {{10}^{-3}}}{4\pi \times {{10}^{-7}}\times 20\times 100}\] =\[7.9\,amp=8amp\]


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