A) \[\frac{B}{2}\]
B) \[\frac{B}{4}\]
C) 2B
D) 4B
Correct Answer: C
Solution :
\[B\propto \frac{1}{r}\Rightarrow \frac{{{B}_{1}}}{{{B}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\Rightarrow \frac{B}{{{B}_{2}}}=\frac{r/2}{r}\Rightarrow {{B}_{2}}=2B\]
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