A) 1/13
B) 3/13
C) 2/13
D) None of these
Correct Answer: C
Solution :
Let X denote a random variable which is the number of aces. Clearly, X takes values, 1, 2. \ \[p=\frac{4}{52}=\frac{1}{13},\] \[q=1-\frac{1}{13}=\frac{12}{13}\] \[P(X=1)=2\times \left( \frac{1}{13} \right)\times \left( \frac{12}{13} \right)=\frac{24}{169}\] \[P(X=2)=2.{{\left( \frac{1}{13} \right)}^{2}}{{\left( \frac{12}{13} \right)}^{0}}=\frac{1}{169}\] Mean = \[\sum\limits_{{}}^{{}}{{{P}_{i}}{{X}_{i}}}=\frac{24}{169}+\frac{2}{169}=\frac{26}{169}=\frac{2}{13}\].
You need to login to perform this action.
You will be redirected in
3 sec
