A) \[\frac{28}{256}\]
B) \[\frac{219}{256}\]
C) \[\frac{128}{256}\]
D) \[\frac{37}{256}\]
Correct Answer: A
Solution :
\[\left. \begin{matrix} np=4 \\ npq=2 \\ \end{matrix} \right\}\Rightarrow q=\frac{1}{2},\,p=\frac{1}{2},\,p=\frac{1}{2},n=8\] \[P(X=2)={{\,}^{8}}{{C}_{2}}{{\left( \frac{1}{2} \right)}^{2}}{{\left( \frac{1}{2} \right)}^{6}}=28.\frac{1}{{{2}^{8}}}=\frac{28}{256}\].
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