A) \[\frac{1}{2}\]
B) \[\frac{1}{8}\]
C) \[\frac{3}{8}\]
D) None of these
Correct Answer: A
Solution :
Let p = Probability of getting tail = \[\frac{1}{2}\] q = Probability of getting head = \[\frac{1}{2}\] Also, \[p+q=1\] and \[n=100\] \[\therefore \] Required probability = \[P(X=1)+P(X=3)+.....+P(X=99)\] = \[^{100}{{C}_{1}}p.{{q}^{99}}{{+}^{100}}{{C}_{3}}{{p}^{3}}{{q}^{97}}+........{{+}^{100}}{{C}_{99}}{{p}^{99}}{{q}^{1}}\] = \[\frac{{{(p+q)}^{100}}-{{(p-q)}^{100}}}{2}=\frac{1}{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
