A) \[\frac{512}{513}\]
B) \[\frac{105}{512}\]
C) \[\frac{100}{153}\]
D) \[{}^{10}{{C}_{6}}\]
Correct Answer: B
Solution :
p = P (getting a head) \[=\frac{1}{2},\,q=\frac{1}{2}.\] \ Required probability = P(six successes) \[={{\,}^{10}}{{C}_{6}}{{\left( \frac{1}{2} \right)}^{6}}\,\,{{\left( \frac{1}{2} \right)}^{4}}\]\[=\frac{10\,!}{6\,!\,4!}\,.\,\frac{1}{{{2}^{10}}}=\frac{105}{512}\].
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