A) \[\frac{1}{32}\]
B) \[\frac{1}{16}\]
C) \[\frac{3}{16}\]
D) \[\frac{5}{16}\]
Correct Answer: D
Solution :
Condition for sum of 12 is 2, 2, 2, 3, 3 \[\therefore \]Required probability \[={{\,}^{5}}{{C}_{3}}{{\left( \frac{1}{2} \right)}^{3}}\,{{\left( \frac{1}{2} \right)}^{2}}\]\[=10.\frac{1}{{{2}^{5}}}=\frac{5}{16}.\]
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