A) \[\frac{9}{25}\]
B) \[\frac{16}{25}\]
C) \[\frac{4}{5}\]
D) \[\frac{8}{25}\]
Correct Answer: B
Solution :
Here \[P\](without defected) \[=\frac{8}{10}=\frac{4}{5}=p\] \[P\](defected) \[=\frac{2}{10}=\frac{1}{5}=q\] and \[n=2,\] \[r=2\] Hence required probability \[={}^{n}{{C}_{r}}{{p}^{r}}.{{q}^{n-r}}\] \[={}^{2}{{C}_{2}}{{\left( \frac{4}{5} \right)}^{2}}.{{\left( \frac{1}{5} \right)}^{0}}=\frac{16}{25}.\]You need to login to perform this action.
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