A) \[\mu =1,\,\,{{\sigma }^{2}}=2/3\]
B) \[\mu =2/3,\,\,{{\sigma }^{2}}=1\]
C) \[\mu =2,\,\,{{\sigma }^{2}}=2/3\]
D) None of these
Correct Answer: A
Solution :
For binomial distribution, mean\[=np\] and variance \[=npq\] \[n=3,\] \[p=\frac{2}{6}=\frac{1}{3},\] \[q=1-p=1-\frac{1}{3}=\frac{2}{3}\] So, mean \[(\mu )=3\times \frac{1}{3}=1\] Variance \[({{\sigma }^{2}})=3\times \frac{1}{3}\times \frac{2}{3}=\frac{2}{3}\].
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