JEE Main & Advanced Mathematics Probability Question Bank Binomial distribution

  • question_answer
    The probability of a bomb hitting a bridge is \[\frac{1}{2}\]and two direct hits are needed to destroy it. The least number of bombs required so that the probability of the bridge beeing destroyed is greater then 0.9, is

    A)                 8             

    B)                 7

    C)                 6             

    D)                 9

    Correct Answer: A

    Solution :

               Let \[n\] be the least number of bombs required and \[X\] the number of bombs that hit the bridge. Then \[X\] follows a binomial distribution with parameter \[n\] and \[p=\frac{1}{2}.\]            Now \[P(X\ge 2)>0.9\Rightarrow 1-P(X<2)>0.9\]            \[\Rightarrow P(X=0)+P(X=1)<0.1\]            \[\Rightarrow {}^{n}{{C}_{0}}{{\left( \frac{1}{2} \right)}^{n}}+{}^{n}{{C}_{1}}{{\left( \frac{1}{2} \right)}^{n-1}}\left( \frac{1}{2} \right)<0.1\Rightarrow 10(n+1)<{{2}^{n}}\]                 This gives \[n\ge 8.\]


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