A) \[{{\left( \frac{2}{3}+\frac{1}{3} \right)}^{6}}\]
B) \[{{\left( \frac{2}{3}+\frac{1}{3} \right)}^{9}}\]
C) \[{{\left( \frac{1}{3}+\frac{2}{3} \right)}^{6}}\]
D) \[{{\left( \frac{1}{3}+\frac{2}{3} \right)}^{9}}\]
Correct Answer: D
Solution :
\[np=6\] \[npq=2\Rightarrow q=\frac{1}{3},\,\,p=\frac{2}{3}\] and \[n=9.\] Hence the binomial distribution is \[{{\left( \frac{1}{3}+\frac{2}{3} \right)}^{9}}.\]
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