JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    The wavelength of a particle is 99 cm and that of other is 100 cm. Speed of sound is 396 m/s. The number of beats heard is                                                      [DCE 2001]

    A)            4    

    B)            5

    C)            1    

    D)            8

    Correct Answer: A

    Solution :

               \[\Delta n=v\left[ \frac{1}{{{\lambda }_{1}}}-\frac{1}{{{\lambda }_{2}}} \right]=396\,\left[ \frac{1}{0.99}-\frac{1}{1} \right]=3.96\approx 4.\]


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