A) 460 Hz
B) 470 Hz
C) 480 Hz
D) 490 Hz
Correct Answer: B
Solution :
If suppose nS = frequency of string \[=\frac{1}{2l}\sqrt{\frac{T}{m}}\] nf = Frequency of tuning fork = 480 Hz x = Beats heard per second = 10 as tension T increases, so nS increases () Also it is given that number of beats per sec decreases (i.e. x¯) Hence nS ? nf = x¯ ... (i) Wrong nf ? nS = x¯ ... (ii) Correct Þ nS = nf ? x = 480 ? 10 = 470 Hz.You need to login to perform this action.
You will be redirected in
3 sec