JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    The velocity of sound is vs in air. If the density of air is increased to 4 times, then the new velocity of sound will be [BHU 2003]

    A)            \[\frac{{{v}_{s}}}{2}\]       

    B)            \[\frac{{{v}_{s}}}{12}\]

    C)            \[12{{v}_{s}}\]                     

    D)                 \[\frac{3}{2}v_{s}^{2}\]

    Correct Answer: A

    Solution :

               \[{{v}_{sound}}\propto \frac{1}{\sqrt{\rho }}\Rightarrow \frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{\rho }_{2}}}{{{\rho }_{1}}}}=\sqrt{\frac{4}{1}}=2\]\[\Rightarrow \]\[{{v}_{2}}=\frac{{{v}_{1}}}{2}=\frac{{{v}_{s}}}{2}\]


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