A) \[0.03\] moles
B) \[0.04\] moles
C) \[0.05\] moles
D) \[0.01\] moles
Correct Answer: C
Solution :
Gram molecular weight of \[N{{a}_{2}}C{{O}_{3}}=2\times 23\times 12+3\times 16=106\,\,g\] \[n=\frac{5.3}{106}=0.05\,\,\text{moles}\]You need to login to perform this action.
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