A) \[29.88\times {{10}^{23}}g\]
B) \[2.988\times {{10}^{23}}g\]
C) \[0.2988\times {{10}^{23}}g\]
D) \[2.988\times {{10}^{-23}}g\]
Correct Answer: D
Solution :
Weight of \[1\] molecule of\[{{H}_{2}}O\] \[\text{=}\frac{\text{Gram}\,\,\text{molecular}\,\,\text{weight}\,\,\text{of}\,\,{{\text{H}}_{\text{2}}}\text{O}}{\text{Avogadro }\!\!'\!\!\text{ s}\,\,\text{number}}\] \[=\frac{18}{6.023\times {{10}^{23}}}=2.988\times {{10}^{-23}}g\]
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