A) \[30.11\times {{10}^{23}}\]atoms
B) \[3.11\times {{10}^{23}}\]atoms
C) \[3.0115\times {{10}^{22}}\]atoms
D) \[301.1\times {{10}^{23}}\]atoms
Correct Answer: C
Solution :
\[1\] mole of iron \[=\] gram atomic mass of iron\[=56\] grams We know that \[1\] mole of iron element contains \[6.023\times {{10}^{23}}\] atoms of iron. \[56\,\,g\] of iron contains \[=6.023\times {{10}^{23}}\] atoms\[2.8\,\,g\] of iron contains \[=\frac{6.023\times {{10}^{23}}}{56}\times 28=\frac{6.023\times {{10}^{22}}}{2}\]\[=3.0115\times {{10}^{22}}\]atoms
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