A) 16 : 1
B) 18 : 1
C) 4 : 1
D) 2 : 1
Correct Answer: D
Solution :
\[{{r}_{n}}\propto {{n}^{4}}\]Þ \[{{A}_{n}}\propto {{n}^{4}}\] Þ \[\frac{{{A}_{1}}}{{{A}_{0}}}={{\left( \frac{2}{1} \right)}^{4}}=\frac{16}{1}\]
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