Answer:
Let the no. of electrons be x. Given:\[x\]( mass of single electron) = the total mass of neutrons present in one calcium atom. \[\Rightarrow \]\[x(~0.00054)=\]No. of neutrons in calcium atom \[\times \]mass of each neutron \[\Rightarrow \] \[x(~0.00054\text{ })=20\times 1.00866\] \[\Rightarrow \] \[x=\frac{20\times 1.00866}{0.00054}\cong 37358\]
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