Answer:
In ?X?,\[{{5}^{th}}\]electron of 3rd shell is its last electron \[\Rightarrow \]\[E.C.=2,\text{ }8,\text{ }5\] In ?Y?, 7th electron of 3rd shell is its last electron \[\Rightarrow \] \[E.C.=2,\text{ }8,\text{ }7\] (a) The no. of electrons in X and Y are 15 and 17 respectively. Hence, X and Y are phosphorus and chlorine respectively. b)\[X{{Y}_{3}}\] (c) 4 (\[{{P}_{4}}\]) and 2 (\[C{{l}_{2}}\]) respectively. (d) No. of neutrons in X i.e., \[P=31-15=16;\] No. of neutrons in Y i.e., \[Cl=35-17=18\] Therefore the ratio\[=8\text{ }:\text{ }9\]
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