Answer:
From the representation it is clear that Z and A of element is 16 and 32 respectively. (i) No. of protons = 16 : No. of electrons = 16 : No. of neutrons\[=32-16=16\]. (ii) No. of nucleons\[=A=32\] (iii) Total mass of electrons = Total no. of electrons\[\times \]mass of each electron. \[=16\times 9.1\times {{10}^{28}}g\] (\[\because \]mass of one electron \[=9.1\times {{10}^{28}}g\]) Total mass of protons = Total no. of protons\[\times \]mass of each proton. \[=16\times 1.675\times {{10}^{24}}g\] (\[\because \]mass of one proton\[=1.672\times {{10}^{24}}g\]) Total mass of protons = Total no. of neutrons \[\times \] mass of each neutron. \[=16\times 1.678\times {{10}^{24}}g\] (\[\because \]mass of one neutron\[=1.672\times {{10}^{24}}g\]) (iv) No. of atoms of X \[=\frac{Total\text{ }mass\text{ }of\text{ }X}{Mass\text{ }of\text{ }single\text{ }atom\text{ }of\text{ }X}\] Mass of single atom of\[X=32\text{ }amu\] \[=32\times 1.66\times {{10}^{-24}}g\] \[(\because 1a.m.u.=1.66\times {{10}^{-24}}g)\] Substituting the value, we get No. of atoms of X \[=\frac{32}{32\times 1.66\times {{10}^{-24}}}=6.023\times {{10}^{23}}\] (v) Atomic number of\[X=16-\]Electronic configuration \[-1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{4}}\] (vi) No. of valence electrons = 6 (vii) Valency \[=86=2\] (viii) XO (ix) E.C.- 2, 8, 6\[\Rightarrow \]No. of electrons are present in L shell of \[X=8\]. (x) Sulphur
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