A) \[NaCl\]
B) \[CsF\]
C) \[NaI\]
D) \[{{K}_{2}}S\]
Correct Answer: D
Solution :
\[{{K}_{2}}S\] formed by \[{{K}^{+}}\]and \[{{S}^{2-}}\] ion. We know that atomic number of K is 19 and in \[{{K}^{+}}\]ion its atomic number would be 18 similarly atomic number of S is 16 and in form \[{{S}^{2-}}\] ion its atomic number would be 18 so the \[{{K}^{+}}\]and \[{{S}^{2-}}\]are isoelectronic with each other in \[{{K}_{2}}S\].
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