JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer 1.520 g of the hydroxide of a metal on ignition gave      0.995 gm of oxide. The equivalent weight of metal is [DPMT 1984]

    A)                 1.520     

    B)                 0.995

    C)                 19.00     

    D)                 9.00

    Correct Answer: D

    Solution :

               \[\frac{\text{wt}\text{. of metal hydroxide }}{\text{wt}\text{. of metal oxide}}=\frac{EM+EO{{H}^{-}}}{EM+E{{O}^{-}}}\] \[=\frac{1.520}{0.995}=\frac{x+17}{x+8}\] \[=1.520x+1.520\times 8\]\[=0.995x+0.995\times 17\]                    \[1.520x+12.160=0.995x+16.915\]                    or \[0.525x=4.755\]                                 \[x=\frac{4.755}{0.525}=9\].


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