JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer Boron has two stable isotopes, \[^{10}B\](19%) and \[^{11}B\](81%). The atomic mass that should appear for boron in the periodic table is                                                [CBSE PMT 1990]

    A)                 10.8       

    B)                 10.2

    C)                 11.2       

    D)                 10.0

    Correct Answer: A

    Solution :

               Atomic mass \[=\frac{10\times 19+81\times 11}{100}\]\[=\frac{190+891}{100}\] \[=\frac{1081}{100}\]                                                   \[=10.81\]


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