JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry Question Bank Atomic Molecular and Equivalent masses

  • question_answer In the reaction  \[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to N{{a}_{2}}{{S}_{4}}{{O}_{6}}+2NaI\], the equivalent weight of \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\](mol. wt. = M) is equal to

    A)                 M            

    B)                 \[M/2\]

    C)                 \[M/3\]    

    D)                 \[M/4\]

    Correct Answer: A

    Solution :

               \[\overset{+2}{\mathop{N{{a}_{2}}S{{O}_{3}}}}\,+{{I}_{2}}\to \overset{+2.5}{\mathop{N{{a}_{2}}{{S}_{4}}{{O}_{6}}}}\,+NaI\]                    \[n=2\times 0.5=1\]                                 \[E=\frac{M}{n-\text{factor}}=\frac{M}{1}=M\]

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