A) \[1.06\,{AA}\]
B) \[0.22\,{AA}\]
C) \[0.28\,{AA}\]
D) \[0.53\,{AA}\]
Correct Answer: D
Solution :
Bohr's radius of the hydrogen atom \[r=\frac{{{n}^{2}}\times 0.529{AA}}{z}\]; where z = Atomic number, n = Number of orbitals
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