10th Class Mathematics Areas Related to Circles Question Bank Assertion And Reason (MCQs) - Areas Related to Circles

  • question_answer
    Assertion (A): If the perimeter of a sector of a circle of radius \[\text{5}.\text{6 cm}\] is \[\text{27}.\text{2 cm},\] then the area of the sector is\[\text{44}.\text{8 c}{{\text{m}}^{\text{2}}}\].
    Reason (R): The area of a sector of a circle of radius r with central angle \[\theta \] is \[\frac{\theta }{360{}^\circ }\times \pi r\].

    A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)

    B) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A)

    C) Assertion (A) is true but Reason (R) is false

    D) Assertion (A) is false but Reason (R) is true

    Correct Answer: C

    Solution :

    [c] Radius of circle \[(r)=5.6m\]
    Let \[\theta \] be the central angle of sector.                      
    Perimeter of sector \[=r+r+\frac{\theta }{360{}^\circ }\times 2\pi r\]
    \[\Rightarrow \,\,\,\,\,\,\,27.2=5.6+5.6+\frac{\theta }{360{}^\circ }\,\,\times 2\times \frac{22}{7}\times 5.6\]
    \[\Rightarrow \,\,\,\,\,\,27.2=11.2+35.2\times \frac{\theta }{360{}^\circ }\Rightarrow 16=35.2\times \frac{\theta }{360{}^\circ }\]\[\Rightarrow \,\,\,\,\,\,\frac{\theta }{360{}^\circ }=\frac{16}{35.2}=\frac{16\times 10}{352}=\frac{5}{11}\]                       ….(1)
    Now, area of sector \[=\frac{\theta }{360{}^\circ }\times \pi {{r}^{2}}\]
    \[=\frac{5}{11}\times \frac{22}{7}\times 5.6\times 5.6\]    [using (i)]
    \[=44.8c{{m}^{2}}\]
    \[\therefore \] Assertion: True; Reason: False.


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