A) 7046 yrs
B) 7.046 yrs
C) 704.6 yrs
D) 70.4 yrs
Correct Answer: D
Solution :
\[t=\frac{2.303}{k}\log \frac{a}{0.99a},(a-x)=\frac{99}{100}=0.99a\] But \[k=\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{10.6}=0.0653\] year?1 \[t=\frac{2.303}{0.0653}\log \frac{1}{0.99}=70.4yrs.\]
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