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JEE Main & Advanced Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Aromatic Hydrocarbon

  • question_answer
    Decreasing order of C-C bond length is [JEE Orissa 2004] \[{{C}_{2}}{{H}_{4}}\] \[{{C}_{2}}{{H}_{2}}\] \[{{C}_{6}}{{H}_{6}}\] \[{{C}_{2}}{{H}_{6}}\]

    A) IV > III > I > II

    B) I > II > IV > III

    C) II > I > IV > III

    D) IV > I > III > II

    Correct Answer: A

    Solution :

               Bond length \[\propto \frac{1}{\text{Bond order}}\]            Bond order = \[\frac{\text{Bonding -- antibonding electron}}{\text{2}}\] Bond order is highest for \[{{C}_{2}}{{H}_{6}}\] so it has minimum bond strength.  


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