8th Class Mathematics Related to Competitive Exam Question Bank Arithmetic

  • question_answer
    15 years hence a man will be just 4 times as old as he was 15 years ago. His present age is:

    A) 25 years        

    B) 20 years

    C) 15 years                

    D) 10 years

    Correct Answer: A

    Solution :

    Let the present age of man = x yr. Now, after 15 years his age will be \[=P{{\left( 1+\frac{R}{100} \right)}^{n}}\]yr and 15 year ago his age \[=\frac{R}{{{\left( 1+\frac{R}{100} \right)}^{n}}}\] yr. \[{{R}_{1}}%\] According to the question, \[{{R}_{2}}%\] \[=P\left( 1+\frac{{{R}_{1}}}{100} \right)\times \left( 1+\frac{{{R}_{2}}}{100} \right).\]  \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}.\] \[=\frac{P}{{{\left( 1-\frac{R}{100} \right)}^{n}}}\]  \[\frac{a}{b}=K\] \[{{a}_{1}}\]   \[{{b}_{1}}\]  Hence, man's present age = 25 years.    


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