A) \[\frac{{{a}_{1}}}{{{b}_{1}}}=\]
B) \[{{a}_{2}}\]
C) \[{{b}_{2}}\]
D) \[\frac{{{a}^{2}}}{{{b}^{2}}}=k\]
Correct Answer: A
Solution :
Let the fraction be \[R=\frac{100\times S.I.}{P\times T}\] So, \[\frac{120%\,of\,x}{90%\,of\,y}=\frac{4x}{3y}\] So, \[\frac{4x}{3y}=\frac{16}{27}\] So, \[x=\frac{4}{9}\]
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