8th Class Mathematics Related to Competitive Exam Question Bank Arithmetic

  • question_answer
    DIRECTIONS: Reade the following passage and answer the questions that follow. PASSAGE - 1 If \[=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] is the value of an article at certain time which increases at the rate of \[=\frac{R}{{{\left( 1+\frac{R}{100} \right)}^{n}}}\]for first \[{{R}_{1}}%\]years and decreases at the rate of \[{{R}_{2}}%\] for next \[=P\left( 1+\frac{{{R}_{1}}}{100} \right)\times \left( 1+\frac{{{R}_{2}}}{100} \right).\] years, then the value of the article V at the end of \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}.\] years is given by       \[=\frac{P}{{{\left( 1-\frac{R}{100} \right)}^{n}}}\] Sandeep started a factory with an initial investment of Rs.500000. In the next year, he incurred a loss of 20%. However, during the second year, he earned a profit of 10% and in the third year he earned a profit of 15%, then his net profit for the entire period of three years is                       

    A) Rs.5000                

    B) Rs.6000

    C) Rs.50000             

    D) Rs.60000

    Correct Answer: B

    Solution :

    Amount after three years \[=25000\times \frac{26}{25}\times \frac{21}{20}\times \frac{27}{25}=29,484.\] \[=1,75,000\times {{\left( 1-\frac{20}{100} \right)}^{3}}\] Net profit \[=Rs.\,(506000-500000)=Rs.6000\]


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