A) \[\Rightarrow \]
B) \[{{a}_{1}}:{{a}_{2}}={{b}_{2}}:{{b}_{1}}\]
C) \[{{a}_{1}}:{{a}_{2}}::{{b}_{2}}:{{b}_{1}}\]
D) \[8\times 32=256,16\times 16=256,32\times 8=256\]
Correct Answer: B
Solution :
Average of \[31\frac{1}{2}=\frac{63}{2},32\frac{1}{2}=\frac{65}{2},31\frac{2}{3}=\frac{95}{3}\]and \[33\frac{3}{4}=\frac{135}{4}\] is given by \[=\frac{(100-5)}{100}\times \frac{(100-10)}{100}\times original=171\] \[\therefore \] \[=171\times \frac{100}{95}\times \frac{100}{90}=Rs.200.\]
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