A) \[a+(n-1)\,d\]
B) \[a+nd\]
C) \[a+(n+1)\,d\]
D) None of these
Correct Answer: B
Solution :
Mean \[=\frac{a+(a+nd)+(a+2nd)}{3}\] \[=\frac{3a+3nd}{3}=a+nd\].
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