A) \[~150\text{ }c{{m}^{2}}\]
B) \[~180\text{ }c{{m}^{2}}\]
C) \[~100\,c{{m}^{2}}\]
D) \[~140\,c{{m}^{2}}\]
Correct Answer: A
Solution :
Area of quadrilateral ABCD \[=\frac{1}{2}\times BD\times AL\times BD\times CM\] \[=\frac{1}{2}\times 20\times 10+\frac{1}{2}\times 20\times 5\] \[=100+50=150\,c{{m}^{2}}\]
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